Question:
The trigonometric function y = tan x in the II quadrant
The trigonometric function y = tan x in the II quadrant
Updated On: Nov 11, 2024
- decrease from 0 to \(\infty\)
- increases from 0 to \(\infty\)
- decrease from -\(\infty\) to 0
- increases from -\(\infty\) to 0
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The correct answer is (D): increases from -\(\infty\) to 0
Was this answer helpful?
1
2
Top Questions on Domain of a Function
- Which one of the following observations is correct for the features of the logarithm function to any base $b > 1$?
- KCET - 2024
- Mathematics
- Domain of a Function
- The function \( f(x) = |x - 24| \) is:
- AP EAMCET - 2024
- Mathematics
- Domain of a Function
- The domain of the real-valued function \( f(x) = \sqrt{9 - \sqrt{x^2 - 144}} \) is
- AP EAMCET - 2024
- Mathematics
- Domain of a Function
- Let A = { x : x ∈ R; x is not a positive integer } Define f : A → R as f(x) = \(\frac{2x}{x-1}\), then f is
- KCET - 2021
- Mathematics
- Domain of a Function
- Domain of the function f(x) = \(\frac{1}{\sqrt{[x]^2-[x]-6}}\) where [x] is greatest integer ≤ x is
- KCET - 2021
- Mathematics
- Domain of a Function
View More Questions
Questions Asked in KCET exam
- A die is thrown 10 times. The probability that an odd number will come up at least once is:
- KCET - 2024
- Probability
- The incorrect statement about the Hall-Heroult process is:
- KCET - 2024
- General Principles and Processes of Isolation of Elements
- Corner points of the feasible region for an LPP are $(0, 2), (3, 0), (6, 0), (6, 8)$ and $(0, 5)$. Let $z = 4x + 6y$ be the objective function. The minimum value of $z$ occurs at:
- KCET - 2024
- Linear Programming Problem
- If a random variable $X$ follows the binomial distribution with parameters $n = 5$, $p$, and $P(X = 2) = 9P(X = 3)$, then $p$ is equal to:
- KCET - 2024
- binomial distribution
- A random variable $X$ has the following probability distribution: \[ \begin{array}{|c|c|c|c|} \hline X & 0 & 1 & 2 \\ \hline P(X) & \frac{25}{36} & k & \frac{1}{36} \\ \hline \end{array} \] If the mean of the random variable $X$ is $\frac{1}{3}$, then the variance is:
- KCET - 2024
- Random Variables and its Probability Distributions
View More Questions