Question:

The total number of products formed in the following reactions:
LiNO3_3 Δ\xrightarrow{\Delta} Products NaNO3_3 Δ\xrightarrow{\Delta} Products Be(NO3_3)2_2 Δ\xrightarrow{\Delta} Products

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Remember the thermal decomposition reactions of alkali metal and alkaline earth metal nitrates.
Updated On: Mar 15, 2025
  • 7
  • 9
  • 6
  • 8
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The Correct Option is D

Solution and Explanation

1. Decomposition of LiNO3_3: * 4LiNO3_3 Δ\xrightarrow{\Delta} 2Li2_2O + 4NO2_2 + O2_2 * Products: Li2_2O, NO2_2, O2_2 (3 products) 
2. Decomposition of NaNO3_3: * 2NaNO3_3 Δ\xrightarrow{\Delta} 2NaNO2_2 + O2_2 * Products: NaNO2_2, O2_2 (2 products) 
3. Decomposition of Be(NO3_3)2_2: * 2Be(NO3_3)2_2 Δ\xrightarrow{\Delta} 2BeO + 4NO2_2 + O2_2 * Products: BeO, NO2_2, O2_2 (3 products) 
Total number of products: * 3 (LiNO3_3) + 2 (NaNO3_3) + 3 (Be(NO3_3)2_2) = 8 products 
Therefore, the total number of products formed is 8. 
Final Answer: 8. 
 

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