Question:
The total number of possible isomers for the complex compound $[Cu^{II}(NH_3)_4] [Pt^{II}Cl_4] $ are
The total number of possible isomers for the complex compound $[Cu^{II}(NH_3)_4] [Pt^{II}Cl_4] $ are
Updated On: Apr 24, 2024
- 5
- 6
- 3
- 4
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The Correct Option is D
Solution and Explanation
Total isomers of the given complex are four.
These are
$(i) [ Cu ( NH_3)_4 ] [PtCl_4 ]$
$(ii) [Cu (NH_3)_3Cl] [Pt(NH_3)Cl_3 ]$
$(hi) [Pt(NH_3)_3Cl] [Cu (NH_3)Cl_3]$
$(iv) [Pt(NH_3)_4] [CuCl_4]$
These are
$(i) [ Cu ( NH_3)_4 ] [PtCl_4 ]$
$(ii) [Cu (NH_3)_3Cl] [Pt(NH_3)Cl_3 ]$
$(hi) [Pt(NH_3)_3Cl] [Cu (NH_3)Cl_3]$
$(iv) [Pt(NH_3)_4] [CuCl_4]$
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.