1μF
2μF
3μF
4μF
The given circuit can be rearranged as
Now the equivalent capacitance of two 1 µF capacitors in parallel is given by
\(Ceq = 1 + 1 = 2 µF\)
AB is a part of an electrical circuit (see figure). The potential difference \(V_A - V_B\), at the instant when current \(i = 2\) A and is increasing at a rate of 1 amp/second is: