Question

The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K, the root mean square speed of gas molecules is v, then at 480 K it will be

• (A) 4v
• (B) 2v
• (C) v/2
• (D) v/4

Answer 1

The Correct Option is B

Explanation:
$\frac{V_1}{V_2}=\sqrt{\frac{T_1}{T_2}}$$\frac{V_1}{V_2}=\sqrt{\frac{120}{480}}-=\sqrt{\frac{1}{4}}=\frac{1}{2}$$V_2=2v$