The sum of the series $S = \frac{1}{19! } + \frac{1}{3!7!} + \frac{1}{5! 5!} + ... $ to 10 terms is equal to :
- $\frac{2^{20}}{20!}$
- $\frac{2^{10}}{20!}$
- $\frac{2^{19}}{19!}$
- $\frac{2^{19}}{20!}$
The Correct Option is B
Solution and Explanation
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