$y^{2} = 4ax$
$\Rightarrow 2\,y \frac{dy}{dx} = 4a$
$\Rightarrow \frac{dy}{dx} = \frac{2a}{y}$
Subtangent $= \frac{y}{dy / dx}=\frac{y}{2\, a/y}$
$= \frac{y^{2}}{2a} = \frac{4ax}{2a}= 2x$
Ordinate $= y = \sqrt{4\,ax} = 2\sqrt{a} \sqrt{x}$
Subnormal $= y \frac{dy}{dx} = 2a$
Since (subtangent) (subnormal) $= \left(2x\right)\left(2a\right)$
$= 4ax =$ (ordinate)$^{2}$
$\Rightarrow$ subtangent, ordinate and subnormal are in $G.P$.