Question:

The static weight on front and rear axles of a two-wheel drive tractor are 3 kN and 9 kN, respectively. The wheel-base of the tractor is 2.1 m and the tractor pulls a load of 7.5 kN. The perpendicular distance from the front wheel ground contact point to the line of pull is 680 mm. Neglecting the wheel contact off-set on the ground, the weight transfer onto the rear axle in kN is _____. \textit{[Round off to two decimal places]}

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The weight transfer to the rear axle can be calculated using the load and the perpendicular distance from the front wheel to the line of pull, normalized by the wheelbase.
Updated On: Nov 27, 2025
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Correct Answer: 2.3

Solution and Explanation

The weight transfer to the rear axle can be calculated using the following equation: \[ \text{Weight transfer} = \frac{P_{\text{load}} \times d}{\text{Wheelbase}} \] where: - \( P_{\text{load}} = 7.5 \, \text{kN} \) is the load being pulled,
- \( d = 680 \, \text{mm} = 0.68 \, \text{m} \) is the perpendicular distance from the front wheel contact point to the line of pull,
- \(\text{Wheelbase} = 2.1 \, \text{m} \). Substitute the values into the formula: \[ \text{Weight transfer} = \frac{7.5 \times 0.68}{2.1} = \frac{5.1}{2.1} \approx 2.43 \, \text{kN}. \] Thus, the weight transfer to the rear axle is approximately \( \boxed{2.43} \, \text{kN} \) (rounded to two decimal places).
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