The statements of pseudocode for searching the first element with key k in the linked list L are given below. Arrange them in the correct order.
(A) while (x != NIL and x.key != k)
(B) x = L.head
(C) x = x.next
(D) return x
Step 1: Understanding the pseudocode.
To search for an element in a linked list, the steps typically follow this flow:
- **(B)** Set `x = L.head`, as the search starts from the head of the linked list.
- **(A)** Use a **while** loop to check that the current node (`x`) is not `NIL` and the key (`x.key`) is not equal to `k`. This continues until the element is found or the end of the list is reached.
- **(C)** Move to the next node by updating `x = x.next`.
- **(D)** If the node with the desired key is found, return `x`.
Step 2: Conclusion.
The correct order of the steps is **(B), (A), (C), (D)**. This order ensures that the search starts at the head, continues through the list, and terminates when the element is found.
In C language, mat[i][j] is equivalent to: (where mat[i][j] is a two-dimensional array)
Suppose a minimum spanning tree is to be generated for a graph whose edge weights are given below. Identify the graph which represents a valid minimum spanning tree?
\[\begin{array}{|c|c|}\hline \text{Edges through Vertex points} & \text{Weight of the corresponding Edge} \\ \hline (1,2) & 11 \\ \hline (3,6) & 14 \\ \hline (4,6) & 21 \\ \hline (2,6) & 24 \\ \hline (1,4) & 31 \\ \hline (3,5) & 36 \\ \hline \end{array}\]
Choose the correct answer from the options given below:
Match LIST-I with LIST-II
Choose the correct answer from the options given below:
Consider the following set of processes, assumed to have arrived at time 0 in the order P1, P2, P3, P4, and P5, with the given length of the CPU burst (in milliseconds) and their priority:
\[\begin{array}{|c|c|c|}\hline \text{Process} & \text{Burst Time (ms)} & \text{Priority} \\ \hline \text{P1} & 10 & 3 \\ \hline \text{P2} & 1 & 1 \\ \hline \text{P3} & 4 & 4 \\ \hline \text{P4} & 1 & 2 \\ \hline \text{P5} & 5 & 5 \\ \hline \end{array}\]
Using priority scheduling (where priority 1 denotes the highest priority and priority 5 denotes the lowest priority), find the average waiting time.