Step 1: Use the truth table or logic laws.
Step 2: $[ A \wedge (\sim A \vee B) ] \to B \equiv [ (A \wedge \sim A) \vee (A \wedge B) ] \to B$.
Step 3: $[ False \vee (A \wedge B) ] \to B \equiv (A \wedge B) \to B$.
Step 4: $(A \wedge B) \to B$ is always true (Tautology), as if $A$ and $B$ are true, $B$ is certainly true.