Question:

The standard reduction potentials of \( 2H^+/H_2 \), \( Cu^{2+}/Cu \), \( Zn^{2+}/Zn \), and \( NO_3^-/HNO_3 \) are 0.0 V, 0.34 V, -0.76 V, and 0.97 V respectively. Identify the correct statements from the following:
I. \( H^+ \) does not oxidize \( Cu \) to \( Cu^{2+} \). 
II. \( Zn \) reduces \( Cu^{2+} \) to \( Cu \). 
III. \( NO_3^- \) oxidizes \( Cu \) to \( Cu^{2+} \).

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Oxidation occurs when a species loses electrons, while reduction occurs when a species gains electrons. The species with a higher reduction potential acts as an oxidizing agent.
Updated On: Mar 24, 2025
  • I, II only
  • I, II , III
  • I, III only
  • II, III only
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The Correct Option is B

Solution and Explanation

Step 1: Understanding Standard Reduction Potentials 
\(E^\circ_{\text{red}} (H^+/H_2) = 0.00V, E^\circ_{\text{red}} (Cu^{2+}/Cu) = 0.34V, E^\circ_{\text{red}} (Zn^{2+}/Zn) = -0.76V,\)
\(E^\circ_{\text{red}} (NO_3^-/HNO_3) = 0.97V\)

Step 2: Evaluating Statements - Statement I: 
- \( H^+ \) can only oxidize a metal if its reduction potential is higher than 0.00V.
- \( Cu \) has \( 0.34V \), which is higher than \(H^+\).
- \( H^+ \) cannot oxidize \( Cu \) to \( Cu^{2+} \) . - Statement II: 
- \( Zn \) has a lower reduction potential (-0.76V) than \( Cu^{2+}/Cu (0.34V) \).
- \( Zn \) is a stronger reducing agent, so it can reduce \( Cu^{2+} \) to \( Cu \).
- This statement is correct. - Statement III: 
- \( NO_3^- \) has a higher reduction potential (0.97V) than \( Cu^{2+}/Cu (0.34V) \).
- \( NO_3^- \) can oxidize \( Cu \) to \( Cu^{2+} \).
- This statement is correct.

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