(we assume that standard emf of the cell \(E^{\circ}_{cell}\) is known)
For the given equilibrium,
\(Cd^{2+}+4NH_{3} {<=>} Cd(NH_{3})^{2+}_{4}\)
At equilibrium,
\(E^{\circ}_{cell}=0\)
Hence, we can calculate the equilibrium constant for reaction as follows :
\(E^{\circ}_{cell}=\frac{0.0591\,V}{n} log \,K_{c}\)
Where, \(K_{c}\) is unknown
\(E^{\circ}_{cell}=0.21\,V\)
\(0.21\,V=\frac{0.0591}{2}log K_{c}\)
\(log\,K_{c}=\frac{0.21\times2}{0.0591}\)
\(log\,K_{c}=\frac{0.42}{0.0591}=7.1065\)
\(K_{c}=1.27\times10^{7}\)
The largest potential difference between two electrodes of a cell, while no current is being pulled from the cell, is known as the electromotive force, or EMF. The charges in an electric circuit move, and in order for the charges in a specific electric circuit to move, we must apply an external force to that electric circuit.
A battery or any other possible difference-making mechanism can serve as the source of an external force. The electromotive force, which is applied by the external electric source and accelerates the charges, is a physical force.
Considering the formula for electromotive force as,
ε = V + Ir
Where
Kp is the equilibrium constant determined from the partial pressure of the equation of a reaction. It's a mathematical expression to determine the relation between product and reactant pressures. Although it connects the pressures, it is a unitless number.
Kc is the equilibrium constant for a reversible reaction, which depicts the ratio of the equilibrium concentrations of products over the concentrations of reactants, where each is raised to the power of their stoichiometric coefficients.
The molar conductance of an infinitely dilute solution of ammonium chloride was found to be 185 S cm$^{-1}$ mol$^{-1}$ and the ionic conductance of hydroxyl and chloride ions are 170 and 70 S cm$^{-1}$ mol$^{-1}$, respectively. If molar conductance of 0.02 M solution of ammonium hydroxide is 85.5 S cm$^{-1}$ mol$^{-1}$, its degree of dissociation is given by x $\times$ 10$^{-1}$. The value of x is ______. (Nearest integer)
Consider the following half cell reaction $ \text{Cr}_2\text{O}_7^{2-} (\text{aq}) + 6\text{e}^- + 14\text{H}^+ (\text{aq}) \longrightarrow 2\text{Cr}^{3+} (\text{aq}) + 7\text{H}_2\text{O}(1) $
The reaction was conducted with the ratio of $\frac{[\text{Cr}^{3+}]^2}{[\text{Cr}_2\text{O}_7^{2-}]} = 10^{-6}$
The pH value at which the EMF of the half cell will become zero is ____ (nearest integer value)
[Given : standard half cell reduction potential $\text{E}^\circ_{\text{Cr}_2\text{O}_7^{2-}, \text{H}^+/\text{Cr}^{3+}} = 1.33\text{V}, \quad \frac{2.303\text{RT}}{\text{F}} = 0.059\text{V}$
| Concentration of KCl solution (mol/L) | Conductivity at 298.15 K (S cm-1) | Molar Conductivity at 298.15 K (S cm2 mol-1) |
|---|---|---|
| 1.000 | 0.1113 | 111.3 |
| 0.100 | 0.0129 | 129.0 |
| 0.010 | 0.00141 | 141.0 |


An electrochemical cell is a device that is used to create electrical energy through the chemical reactions which are involved in it. The electrical energy supplied to electrochemical cells is used to smooth the chemical reactions. In the electrochemical cell, the involved devices have the ability to convert the chemical energy to electrical energy or vice-versa.