Question:

The spin-only magnetic moment of Hexacyanomanganate(II) ion is.........BM

Updated On: Mar 27, 2025
  • 1.73 BM

  • 5.90 BM

     

  • 4.90 BM
  • 3.87 BM
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The Correct Option is A

Solution and Explanation

Option 2: 1.73 BM

To determine the spin-only magnetic moment of the Hexacyanomanganate(II) ion, [Mn(CN)6]4-, we need to find the number of unpaired electrons in the Mn2+ ion.

1. Electronic configuration of Mn:

Mn (Z = 25): [Ar] 3d5 4s2

2. Electronic configuration of Mn2+:

Mn2+: [Ar] 3d5

3. Effect of CN- ligand:

CN- is a strong field ligand. In the presence of strong field ligands, the d-electrons pair up. However, since there are 5 d-electrons, there will be one unpaired electron in the t2g orbital. The configuration will be t2g5eg0

4. Number of unpaired electrons (n):

n = 1

5. Spin-only magnetic moment formula:

μs = √[n(n+2)] BM

6. Calculation:

μs = √[1(1+2)] BM

μs = √[1(3)] BM

μs = √3 BM

μs ≈ 1.73 BM

Therefore, the spin-only magnetic moment of [Mn(CN)6]4- is approximately 1.73 BM.

The correct answer is:

Option 2: 1.73 BM

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