The speed of light in benzene is 2×108 m/s. Its refractive index is (speed of light in vacuum = 3x108m/s)
- 0.66
- 1
- 1.5
- 2
The Correct Option is C
Solution and Explanation
Correct answer: 1.5
The refractive index \( n \) is calculated using the formula: \[ n = \frac{c}{v} \] where: - \( c = 3 \times 10^8 \, \text{m/s} \) (speed of light in vacuum) - \( v = 2 \times 10^8 \, \text{m/s} \) (speed of light in benzene) \[ n = \frac{3 \times 10^8}{2 \times 10^8} = 1.5 \] Hence, the correct answer is 1.5.
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