Question:

The speed of a wave is \( 30 \, \mathrm{m/s} \). If the distance between 11 crests is \( 1 \, \mathrm{m} \), what is the frequency (in Hz)?

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Updated On: Jan 25, 2025
  • \( 300 \, \mathrm{Hz} \)
  • \( 330 \, \mathrm{Hz} \)
  • \( 350 \, \mathrm{Hz} \)
  • \( 360 \, \mathrm{Hz} \)
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The Correct Option is A

Solution and Explanation

The wavelength (\( \lambda \)) of a wave is the distance between two consecutive crests. When there are 11 crests, the distance between them corresponds to 10 wavelengths: \[ 10 \lambda = 1 \, \mathrm{m}. \] Thus, the wavelength is: \[ \lambda = \frac{1}{10} = 0.1 \, \mathrm{m}. \] The frequency (\( f \)) of a wave is given by the formula: \[ f = \frac{v}{\lambda}, \] where: \( v = 30 \, \mathrm{m/s} \) is the speed of the wave, \( \lambda = 0.1 \, \mathrm{m} \) is the wavelength. Substitute the values: \[ f = \frac{30}{0.1} = 300 \, \mathrm{Hz}. \] Thus, the frequency of the wave is \( \mathbf{300 \, \mathrm{Hz}} \).
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