Question

The specific growth rate of a yeast having a doubling time of 0.693 h (rounded off to nearest integer) is _________ h^-1.

Hint:

Doubling time and growth rate are inversely related: a shorter doubling time means a higher growth rate.

Answer 1

Correct Answer: 1

The relation between doubling time $(t_d)$ and specific growth rate $(\mu)$ is:
\[ t_d = \frac{\ln 2}{\mu} \]
Given doubling time:
\[ t_d = 0.693\; \text{h} \]
Thus,
\[ \mu = \frac{\ln 2}{t_d} = \frac{0.693}{0.693} = 1\; \text{h}^{-1} \]
Rounded to the nearest integer:
\[ \boxed{1} \]