Given inequality:
5(4x + 6) < 25x + 10
Goal: Find the solution set of the inequality.
Step 1: Distribute the 5 on the left-hand side.
5(4x + 6) = 5 * 4x + 5 * 6 = 20x + 30
So, the inequality becomes:
20x + 30 < 25x + 10
Step 2: Move the terms with x to one side and constant terms to the other side.
20x - 25x < 10 - 30
-5x < -20
Step 3: Divide both sides by -5 and reverse the inequality sign.
x > 4
Step 4: Conclusion.
The solution set is (4, ∞).
The feasible region for the inequalities $ x + 2y \geq 4, \quad 2x + y \leq 6, \quad x \geq 0, \quad y \geq 0 $