Step 1: Understanding the differential equation.
We are given the second-order linear homogeneous differential equation:
\[
\frac{d^2 y}{dx^2} - 3 \frac{dy}{dx} + 2y = 0
\]
This is a linear differential equation with constant coefficients. To solve this type of equation, we first write down the characteristic equation and solve for the roots.
Step 2: Finding the characteristic equation.
Assume that the solution is of the form \( y = e^{rx} \), where \( r \) is a constant. Then, we can calculate the first and second derivatives:
\[
\frac{dy}{dx} = r e^{rx}, \quad \frac{d^2 y}{dx^2} = r^2 e^{rx}
\]
Substituting these into the given equation:
\[
r^2 e^{rx} - 3r e^{rx} + 2 e^{rx} = 0
\]
Factor out \( e^{rx} \) (which is never zero):
\[
e^{rx} (r^2 - 3r + 2) = 0
\]
Thus, the characteristic equation is:
\[
r^2 - 3r + 2 = 0
\]
Step 3: Solving the characteristic equation.
Now, solve the quadratic equation \( r^2 - 3r + 2 = 0 \). Factorizing:
\[
(r - 1)(r - 2) = 0
\]
So, the roots are:
\[
r_1 = 1 \quad \text{and} \quad r_2 = 2
\]
Step 4: General solution.
Since the roots \( r_1 = 1 \) and \( r_2 = 2 \) are real and distinct, the general solution to the differential equation is:
\[
y(x) = C_1 e^{r_1 x} + C_2 e^{r_2 x}
\]
Substituting the values of \( r_1 \) and \( r_2 \):
\[
y(x) = C_1 e^x + C_2 e^{2x}
\]
Step 5: Conclusion.
The general solution to the given differential equation is:
\[
y(x) = C_1 e^x + C_2 e^{2x}
\]
Therefore, the correct answer is:
\[
\boxed{\text{(C) } y = C_1 e^x + C_2 e^{2x}}
\]