Question:
The solubility product of barium sulphate is $1.5 \times 10^{-9}$ at 18$^\circ$C. Its solubility in water at 18$^\circ$C is
The solubility product of barium sulphate is $1.5 \times 10^{-9}$ at 18$^\circ$C. Its solubility in water at 18$^\circ$C is
Updated On: Jun 23, 2023
- $1.5 \times 10^{-9} \, mol L^{-1}$
- $1.5 \times 10^{-5} mol \,L^{-1}$
- $3.9 \times 10^{-9} mol \,L^{-1}$
- $3.9 \times 10^{-5} mol \, L^{-1}$.
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The Correct Option is D
Solution and Explanation
$BaSO_{4} \to Ba^{+2}+SO^{2-}_{4}$
$\therefore$ Solubility $=(K_{sp})^{1/2}$
$=(1.5 \times 10^{-9})^{1/2}=3.87\times10^{-5}\,mol\,L^{-1}$
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Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.