Question:

The solubility product of AgCl is $4.0 \times 10^{-10}$ at 298 K. The solubility of AgCl in 0.04 M $CaCl_2$ will be

Updated On: Jun 23, 2023
  • $2.0 \times 10^{-5}M$
  • $1.0 \times 10^{-4}M$
  • $5.0 \times 10^{-9}M$
  • $2.2 \times 10^{-4}M$
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The Correct Option is C

Solution and Explanation

In $CaCl_{2}\cdot [Cl^{-}]=2 \times 0.04=0.08\,mol\,L^{-1}$ $[Cl^{-}]$ from $AgCl$ is too small and is neglected $K_{sp}=[Ag^{+}] [Cl^{-}]$ $4 \times 10^{-10}=[Ag^{+}]\times 0.08$ $4 \times 10^{-10}=[Ag^{+}]\times 0.08$ $\left[Ag^{+}\right]=\frac{4\times10^{-10}}{0.08}=\frac{4}{8}\times10^{-8}$ $=5.0 \times 10^{-9}\,M$
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Concepts Used:

Solutions

A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.

For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.

Types of Solutions:

The solutions can be classified into three types:

  • Solid Solutions - In these solutions, the solvent is in a Solid-state.
  • Liquid Solutions- In these solutions, the solvent is in a Liquid state.
  • Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.

On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:

  1. Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
  2. Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
  3. Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.