Question

The solubility product of AgCl is \(1.8\times10^{-10}\). The solubility in mol/L is:

• A. \(1.8\times10^{-10}\)
• B. \(1.34\times10^{-5}\)
• C. \(1.8\times10^{-5}\)
• D. \(3.6\times10^{-10}\)

Hint:

For 1:1 salts, \(K_{sp}=s^2\).

Answer 1

The Correct Option is B

For AgCl, \(K_{sp}=s^2\): \[ s=\sqrt{1.8\times10^{-10}}=1.34\times10^{-5}\ \text{mol/L} \]