Kinetic energy is $ {KE} = \frac{1}{2} m v^2 $. The slope of the graph is:
\[
\frac{d({KE})}{ds} = \frac{d}{ds} \left( \frac{1}{2} m v^2 \right) = m v \frac{dv}{ds}
\]
Since $ \frac{dv}{ds} = \frac{dv}{dt} \cdot \frac{dt}{ds} = \frac{a}{v} $, where $ a $ is acceleration:
\[
\frac{d({KE})}{ds} = m v \cdot \frac{a}{v} = m a
\]
Since $ m a = F $ (force), the slope represents force, matching option (3).