The slip-speed of a 3-\(\phi\), cage, 50 Hz, induction motor is 20 rpm at no-load. If slip-speed is doubled due to load, then the electrical equivalent of mechanical load will
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Electrical load \( \propto \text{slip}^2 \); doubling slip doesn’t double the load — it increases it sharply.
The electrical equivalent of mechanical load is proportional to the square of the slip. If slip doubles, equivalent load increases more than four times, which effectively means that for a given change in speed, the electrical load changes significantly — not linearly.