The short circuit admittance matrix of a two port network is $\left[\begin{matrix} 0 & \frac{-1}{2} \ \frac{1}{2} & 0 \end{matrix}\right]$ . The given two port network is.

Question

The short circuit admittance matrix of a two port network is $\left[\begin{matrix}   0 & \frac{-1}{2} \   \frac{1}{2} & 0  \end{matrix}\right]$ . The given two port network is.

cdquestions Admin · Accepted Answer

The correct option is(B): Non-reciprocal and active

Answer

Non-reciprocal and passive

Answer

Non-reciprocal and active

Answer

Reciprocal and passive

Answer

Reciprocal and active

The short circuit admittance matrix of a two port network is $\left[\begin{matrix} 0 & \frac{-1}{2} \\ \frac{1}{2} & 0 \end{matrix}\right]$ . The given two port network is.

The Correct Option is B

Solution and Explanation

Questions Asked in CUET PG exam

The short circuit admittance matrix of a two port network is [ 0−12 120 ]\left[\begin{matrix} 0 & \frac{-1}{2} \\ \frac{1}{2} & 0 \end{matrix}\right][ 0 21​​2−1​0 ​]. The given two port network is.

The Correct Option is B

Solution and Explanation

Questions Asked in CUET PG exam

The short circuit admittance matrix of a two port network is $\left[\begin{matrix} 0 & \frac{-1}{2} \\ \frac{1}{2} & 0 \end{matrix}\right]$ . The given two port network is.