The sequence of reagents required to convert ethyl bromide to propanal is:
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- \( CH_3COOAg, \text{DIBAL-H, H}_2O \)
- \( CH_3COOAg, \text{LiAlH}_4, H_2O \)
- \( Mg/ether, HCHO, H_2O \)
- \( CH_3COOH, \text{LiAlH}_4, H_2O \)
The Correct Option is A
Solution and Explanation
Step 1: Understanding the conversion steps
1. Ethyl bromide reacts with silver acetate (CH₃COOAg) to form ethyl acetate.
2. DIBAL-H (Diisobutylaluminium hydride) selectively reduces ethyl acetate to propanal.
3. Hydrolysis ensures complete conversion to aldehyde without further reduction to alcohol.
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