Question:

The satellite of mass m revolving in a circular orbit of radius r around the earth has kinetic energy E. Then its angular momentum will be

Updated On: Jul 7, 2022
  • $\sqrt{\frac{E}{mr^2}}$
  • $\frac{E}{2 mr^2}$
  • $\sqrt{2 E mr^2}$
  • $\sqrt{2 E mr}$
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The Correct Option is C

Solution and Explanation

KE of a satellite $E = \frac{1}{2} mv^2$ or $mv = \sqrt{2 E m}$ Angular momentum $ L = m v r = (\sqrt{2E m}) \times r$ $ = \sqrt{2 m E r^2}$
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Notes on momentum

Concepts Used:

Momentum

It can be defined as "mass in motion." All objects have mass; so if an object is moving, then it is called as momentum.

the momentum of an object is the product of mass of the object and the velocity of the object.

Momentum = mass • velocity

The above equation can be rewritten as

p = m • v

where m is the mass and v is the velocity. 

Momentum is a vector quantity and  the direction of the of the vector is the same as the direction that an object.