Let the salary of Tanu be T and the salary of Manu be M.
According to the given condition, we have:
\[ M = \frac{T}{2} \]
After the changes:
We are also given that Manu’s new salary is 68.75% of Tanu’s new salary. Therefore, we can write the equation:
\[ M + 3000 = 0.6875 \times 0.8T \]
Substitute \( M = \frac{T}{2} \) into this equation:
\[ \frac{T}{2} + 3000 = 0.6875 \times 0.8T \]
Simplify the right side:
\[ \frac{T}{2} + 3000 = 0.55T \]
Multiply the entire equation by 2 to eliminate the fraction:
\[ T + 6000 = 1.1T \]
Rearrange the terms:
\[ 6000 = 1.1T - T \] \[ 6000 = 0.1T \] \[ T = \frac{6000}{0.1} = 60,000 \]
The salary of Tanu is Rs. 60,000.
The correct answer is (d) Rs. 60,000.
List-I | List-II |
---|---|
(A) Confidence level | (I) Percentage of all possible samples that can be expected to include the true population parameter |
(B) Significance level | (III) The probability of making a wrong decision when the null hypothesis is true |
(C) Confidence interval | (II) Range that could be expected to contain the population parameter of interest |
(D) Standard error | (IV) The standard deviation of the sampling distribution of a statistic |