Question:
The salaries of three friends Sita, Gita and Mita are initially in the ratio 5: 6: 7 , respectively. In the first year, they get salary hikes of 20%, 25% and 20% , respectively. In the second year, Sita and Mita get salary hikes of 40% and 25% , respectively, and the salary of Gita becomes equal to the mean salary of the three friends. The salary hike of Gita in the second year is
The salaries of three friends Sita, Gita and Mita are initially in the ratio 5: 6: 7 , respectively. In the first year, they get salary hikes of 20%, 25% and 20% , respectively. In the second year, Sita and Mita get salary hikes of 40% and 25% , respectively, and the salary of Gita becomes equal to the mean salary of the three friends. The salary hike of Gita in the second year is
Updated On: Jan 13, 2026
- 27%
- 24%
- 26%
- 28%
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The Correct Option is C
Solution and Explanation
Let the initial salaries of Sita, Gita, and Mita be:
- Sita: \( 5p \)
- Gita: \( 6p \)
- Mita: \( 7p \)
They receive hikes as follows:
- Sita: 20% hike ⇒ New salary = \( 5p \times \frac{6}{5} = 6p \)
- Gita: 25% hike ⇒ New salary = \( 6p \times \frac{5}{4} = 7.5p \)
- Mita: 20% hike ⇒ New salary = \( 7p \times \frac{6}{5} = 8.4p \)
Now, Sita and Mita get another hike:
- Sita: 40% hike ⇒ New salary = \( 6p \times 1.4 = 8.4p \)
- Mita: 25% hike ⇒ New salary = \( 8.4p \times 1.25 = 10.5p \)
Let Gita's new salary after this round of hike be \( g \).
We are told that the new average salary of all three = average of updated salaries =
\[ \frac{8.4p + g + 10.5p}{3} = g \]
Multiply both sides by 3:
\[ 8.4p + g + 10.5p = 3g \] \[ 18.9p + g = 3g \Rightarrow 2g = 18.9p \Rightarrow g = \frac{18.9p}{2} = 9.45p \]
So, Gita’s new salary is \( 9.45p \).
Gita’s old salary after first hike was \( 7.5p \). Now it is \( 9.45p \).
Hence, the percentage increase in Gita’s salary is:
\[ \frac{9.45p - 7.5p}{7.5p} \times 100 = \frac{1.95p}{7.5p} \times 100 = 26\% \]
Final Answer: 26% (Option C)
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