Question

The resonance frequency of the tank circuit of an oscillator when $ L=\frac{10}{{{\pi }^{2}}}mH $ and $ C=0.04\text{ }\mu F $ are connected in parallel is

• A. 250 kHz
• B. 25 kHz
• C. 2.5 kHz
• D. 25 MHz

Answer 1

The Correct Option is B

In parallel resonant circuit resonance frequency $ {{f}_{o}}=\frac{1}{2\pi \sqrt{LC}}=\frac{1}{2\pi \sqrt{\frac{10\times {{10}^{-3}}}{{{\pi }^{2}}}\times 0.04\times {{10}^{-6}}}} $ $ =\frac{{{10}^{4}}}{2\times 0.2}=25\,kHz $