Question

The resistance of 0.01 m KCl solution at 298 K is 1500Ω. If the conductivity of 0.01 m KCl solution at 298 K is 0.1466 × 10^-3 S cm^-1. The cell constant of the conductivity cell in cm^-1 is

• A. 0.219
• B. 0.291
• C. 0.301
• D. 0.194

Answer 1

The Correct Option is A

1. Recall the relationship between resistance, conductivity, and cell constant
The relationship between resistance (R), conductivity (κ), and cell constant (G^*) is given by:

$R = \frac{1}{\kappa} \times G^*$

where:
- $R$ is the resistance in ohms (Ω)
- $κ$ (kappa) is the conductivity in Siemens per centimeter (S cm^-1)
- $G^*$ is the cell constant in cm^-1

2. Rearrange the formula to solve for the cell constant
We need to find the cell constant, so we rearrange the formula:

$G^* = R \times \kappa$

3. Substitute the given values
We are given:

- $R = 1500$ Ω
- $κ = 0.146 \times 10^{-3}$ S cm^-1

Substitute these values into the formula:

$G^* = 1500 \times (0.146 \times 10^{-3})$ cm^-1

4. Calculate the cell constant
$G^* = 1500 \times 0.000146$ cm^-1
$G^* = 0.219$ cm^-1

Final Answer:
(A) 0.219

Answer 2

The conductivity (κ) is related to resistance (R) and the cell constant (K) by the equation:

\(κ = K × (\frac 1R)\)

Substitute the given values:

\(0.146 × 10^{–3} = K × (\frac {1}{1500})\)

Solve for K:

\(K = (0.146 × 10^{–3}) × 1500\)

\(K = 0.219\)

The correct answer is (A) : 0.219.