Question:
The resistance of 0.01 m KCl solution at 298 K is 1500Ω. If the conductivity of 0.01 m KCl solution at 298 K is 0.1466 × 10-3 S cm-1. The cell constant of the conductivity cell in cm-1 is
The resistance of 0.01 m KCl solution at 298 K is 1500Ω. If the conductivity of 0.01 m KCl solution at 298 K is 0.1466 × 10-3 S cm-1. The cell constant of the conductivity cell in cm-1 is
Updated On: Apr 1, 2025
- 0.219
- 0.291
- 0.301
- 0.194
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The Correct Option is A
Solution and Explanation
The conductivity (κ) is related to resistance (R) and the cell constant (K) by the equation:
\(κ = K × (\frac 1R)\)
Substitute the given values:
\(0.146 × 10^{–3} = K × (\frac {1}{1500})\)
Solve for K:
\(K = (0.146 × 10^{–3}) × 1500\)
\(K = 0.219\)
The correct answer is (A) : 0.219.
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