The relationship between equilibrium constant K and free energy change of the process is given by
- \(\Delta G = -RT\log K\)
- \(\Delta G\degree = RT\log \frac{1}{K}\)
- \(\Delta G\degree = 2RT\log K\)
- \(\Delta G\degree = 2.303RT\log K^{-1}\)
The Correct Option is D
Solution and Explanation
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