Question:

The relationship between equilibrium constant K and free energy change of the process is given by

Updated On: Oct 4, 2024
  • \(\Delta G = -RT\log K\)
  • \(\Delta G\degree = RT\log \frac{1}{K}\)
  • \(\Delta G\degree = 2RT\log K\)
  • \(\Delta G\degree = 2.303RT\log K^{-1}\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

The correct option is (D): \(\Delta G\degree = 2.303RT\log K^{-1}\)
Was this answer helpful?
0
0