The critical angle \( \theta_c \) is the angle of incidence for which the angle of refraction is 90°. It is given by the formula: \[ \sin \theta_c = \frac{n_2}{n_1} \] where \( n_1 \) is the refractive index of the denser medium (glass) and \( n_2 \) is the refractive index of the rarer medium (air). Given that the refractive index of glass with respect to air is 2, we have: \[ \sin \theta_c = \frac{1}{2} \] Now, solving for \( \theta_c \): \[ \theta_c = \sin^{-1} \left( \frac{1}{2} \right) = 30^\circ \]
The correct option is (D): \(30°\)