The reagent, from the following, which converts benzoic acid to benzaldehyde in one step is
The reagent, from the following, which converts benzoic acid to benzaldehyde in one step is
LiAlH4
KMnO4
MnO
NaBH4
The Correct Option is C
Solution and Explanation
The correct answer is (C) : MnO
Benzoic acid can be converted to benzaldehyde in presence of MnO.
Top Questions on Aldehydes, Ketones and Carboxylic Acids
- What do you understand by these following terms? Give one example of each.
(i) Aldol (ii) Schiff's base (iii) Cannizaro's reaction (iv) Oxime (v) Acetal- UP Board XII - 2025
- Chemistry
- Aldehydes, Ketones and Carboxylic Acids
In the given reaction sequence, the structure of Y would be:
- CBSE CLASS XII - 2025
- Chemistry
- Aldehydes, Ketones and Carboxylic Acids
- Identify the sets containing correct order against the property mentioned from the following
- TS EAMCET - 2025
- Chemistry
- Aldehydes, Ketones and Carboxylic Acids
- What are X, Y, Z respectively in the following reaction sequence?
CH$_3$CH=CHCH$_3$ $\xrightarrow{X}$ CH$_3$COOH $\xrightarrow{Y}$ CH$_3$CO-Cl $\xrightarrow{Z, C6H5NH2}$ C$_6$H$_5$NHCOCH$_3$- TS EAMCET - 2025
- Chemistry
- Aldehydes, Ketones and Carboxylic Acids
- An amine X (C4H11N) on heating with CHCl3 in ethanolic KOH forms a foul-smelling substance. Product of other amine Y (C4H11N) and benzenesulphonyl chloride is insoluble in alkali. What are X and Y respectively?
- TS EAMCET - 2025
- Chemistry
- Aldehydes, Ketones and Carboxylic Acids
Questions Asked in JEE Main exam
- A force of 49 N acts tangentially at the highest point of a sphere (solid of mass 20 kg) kept on a rough horizontal plane. If the sphere rolls without slipping, then the acceleration of the center of the sphere is:
- JEE Main - 2025
- Quantum Mechanics
Let \( y^2 = 12x \) be the parabola and \( S \) its focus. Let \( PQ \) be a focal chord of the parabola such that \( (SP)(SQ) = \frac{147}{4} \). Let \( C \) be the circle described by taking \( PQ \) as a diameter. If the equation of the circle \( C \) is: \[ 64x^2 + 64y^2 - \alpha x - 64\sqrt{3}y = \beta, \] then \( \beta - \alpha \) is equal to:
- JEE Main - 2025
- Parabola
The expression given below shows the variation of velocity \( v \) with time \( t \): \[ v = \frac{At^2 + Bt}{C + t} \] The dimension of \( A \), \( B \), and \( C \) is:
- JEE Main - 2025
- Dimensional Analysis
The dimensions of a physical quantity \( \epsilon_0 \frac{d\Phi_E}{dt} \) are similar to [Symbols have their usual meanings]
- JEE Main - 2025
- Dimensional analysis
- Match List-I with List-II.
- JEE Main - 2025
- Dimensional analysis