Question

The ratio of volume of Al²⁷ nucleus to its surface area is (Given R₀= 1.2x10^-15 m)

• A. 2.1x10^-15 m
• B. 1.3x10^-15 m
• C. 0.22x10^-15 m
• D. 1.2x10^-15 m

Answer 1

The Correct Option is D

The volume \( V \) and surface area \( A \) of a nucleus are given by: \[ V \propto R^3, \quad A \propto R^2 \] where \( R \) is the radius of the nucleus. The ratio of volume to surface area is: \[ \frac{V}{A} \propto \frac{R^3}{R^2} = R \] Given that \( R_0 = 1.2 \times 10^{-15} \, \text{m} \), the ratio of volume to surface area is \( R_0 \). Thus, the solution is \( 1.2 \times 10^{-15} \, \text{m} \).