The ratio of the speed of sound in helium gas to that in nitrogen gas at same temperature is (γHe = \(\frac {5}{3}\), γN2 = 4 , M N2 =28)
\(\frac {5}{\sqrt {3}}\)
\(\sqrt{\frac {7}{5}}\)
\(\sqrt{\frac {2}{7}}\)
\(\sqrt{\frac {5}{3}}\)
We know that
v = \(\sqrt {\frac {rRT}{M}}\)
\(\frac {v_{He}}{v_{N_2}}\) = \(\frac {\sqrt {\frac {5/3 RT}{4}}}{\sqrt {\frac {7/5 RT}{14}}}\)
\(\frac {v_{He}}{v_{N_2}}\) = \(\sqrt {\frac {5\times 28}{7R}} \sqrt {\frac {5RT}{3\times 4}}\)
\(\frac {v_{He}}{v_{N_2}}\) = \(\frac {5}{\sqrt {3}}\)
Therefore the correct option is (A) \(\frac {5}{\sqrt {3}}\)
Two loudspeakers (\(L_1\) and \(L_2\)) are placed with a separation of \(10 \, \text{m}\), as shown in the figure. Both speakers are fed with an audio input signal of the same frequency with constant volume. A voice recorder, initially at point \(A\), at equidistance to both loudspeakers, is moved by \(25 \, \text{m}\) along the line \(AB\) while monitoring the audio signal. The measured signal was found to undergo \(10\) cycles of minima and maxima during the movement. The frequency of the input signal is _____________ Hz.
(Speed of sound in air is \(324 \, \text{m/s}\) and \( \sqrt{5} = 2.23 \)) 