In simple harmonic motion, the kinetic energy and potential energy of the pendulum are equal at the point of maximum amplitude (extreme displacement). \[ {Kinetic Energy} = \frac{1}{2} m v^2 \quad {and} \quad {Potential Energy} = \frac{1}{2} k x^2 \] At the extreme position, all the energy is potential, and at the equilibrium point, all the energy is kinetic.
Therefore, the ratio of the maximum kinetic energy to the maximum potential energy is 1:1.
Hence, the correct answer is (A).
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: