In simple harmonic motion, the kinetic energy and potential energy of the pendulum are equal at the point of maximum amplitude (extreme displacement). \[ {Kinetic Energy} = \frac{1}{2} m v^2 \quad {and} \quad {Potential Energy} = \frac{1}{2} k x^2 \] At the extreme position, all the energy is potential, and at the equilibrium point, all the energy is kinetic.
Therefore, the ratio of the maximum kinetic energy to the maximum potential energy is 1:1.
Hence, the correct answer is (A).
A particle is subjected to simple harmonic motions as: $ x_1 = \sqrt{7} \sin 5t \, \text{cm} $ $ x_2 = 2 \sqrt{7} \sin \left( 5t + \frac{\pi}{3} \right) \, \text{cm} $ where $ x $ is displacement and $ t $ is time in seconds. The maximum acceleration of the particle is $ x \times 10^{-2} \, \text{m/s}^2 $. The value of $ x $ is:
Two simple pendulums having lengths $l_{1}$ and $l_{2}$ with negligible string mass undergo angular displacements $\theta_{1}$ and $\theta_{2}$, from their mean positions, respectively. If the angular accelerations of both pendulums are same, then which expression is correct?