Question:
The ratio of radii of 3rd and 6th Bohr’s orbits in a hydrogen atom is:
The ratio of radii of 3rd and 6th Bohr’s orbits in a hydrogen atom is:
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Bohr orbit radius is proportional to \(n^2\): \( r_n \propto n^2 \)
Updated On: May 17, 2025
- \(0.25\)
- \(0.33\)
- \(4\)
- \(3\)
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The Correct Option is A
Solution and Explanation
Bohr’s radius is given by:
\[
r_n \propto n^2
\Rightarrow \frac{r_3}{r_6} = \frac{3^2}{6^2} = \frac{9}{36} = \frac{1}{4} = 0.25
\]
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