Question:

The ratio of modulus of rigidity to bulk modulus for a Poisson's ratio of 0.25 would be:

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Understanding the relationships between different elastic constants is crucial for material selection and mechanical design.
Updated On: Feb 7, 2025
  • \( \frac{2}{3} \)
  • \( \frac{2}{5} \)
  • \( \frac{3}{5} \)
  • \( 1 \)
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The Correct Option is A

Solution and Explanation

Using the relationship between Young's modulus (E), modulus of rigidity (G), and bulk modulus (K) with Poisson's ratio (\(\nu\)): \[ G = \frac{E}{2(1+\nu)} \quad \text{and} \quad K = \frac{E}{3(1-2\nu)} \] For \(\nu = 0.25\), the ratio \( \frac{G}{K} \) becomes: \[ \frac{G}{K} = \frac{\frac{E}{2(1+0.25)}}{\frac{E}{3(1-2 \times 0.25)}} = \frac{3}{2} \times \frac{1.5}{2} = \frac{9}{12} = \frac{3}{4} \]
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