Question:

The ratio mass of oxygen and nitrogen of a particular gaseous mixture is $1 : 4$ The ratio of number of their molecule is

Updated On: Jun 23, 2024
  • $1 : 4$
  • $7 : 32$
  • $1 : 8$
  • $3 : 16$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Let the mass of $O _{2}= x$ Mass of $N _{2}=4 x$ Number of moles of $ O _{2}=\frac{ x }{32}$ Number of moles of $ N _{2}=\frac{4 x }{28}=\frac{x}{7}$ $\therefore$ Ratio $=\frac{x}{32}: \frac{x}{7}=7: 32$
Was this answer helpful?
0
0

Top Questions on Ideal gas equation

View More Questions

Concepts Used:

Ideal Gas Equation

An ideal gas is a theoretical gas composed of a set of randomly-moving point particles that interact only through elastic collisions.

What is Ideal Gas Law?

The ideal gas law states that the product of the pressure and the volume of one gram molecule of an ideal gas is equal to the product of the absolute temperature of the gas and the universal gas constant.

PV=nRT

where,

P is the pressure

V is the volume

n is the amount of substance

R is the ideal gas constant

Ideal Gas Law Units

When we use the gas constant R = 8.31 J/K.mol, then we have to plug in the pressure P in the units of pascals Pa, volume in the units of m3 and the temperature T in the units of kelvin K.