Question:
The rate of diffusion of methane at a given temperature is twice of a gas X. The molar mass of the gas X is:
The rate of diffusion of methane at a given temperature is twice of a gas X. The molar mass of the gas X is:
Updated On: Jun 6, 2022
- 64
- 32
- 16
- 8
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The Correct Option is A
Solution and Explanation
Relation between rate of diffusions and molar masses of the gases X and
$ C{{H}_{4}} $ is $ \frac{{{r}_{x}}}{{{r}_{C{{H}_{4}}}}}=\sqrt{\frac{{{M}_{C{{H}_{4}}}}}{{{M}_{x}}}} $
Let the rate of diffusion of gas
$ X=a $ $ \therefore $
$ \frac{a}{2a}=\sqrt{\frac{16}{{{M}_{X}}}} $
( $ \because $ $ C{{H}_{4}}=12.4=16 $ )
$ \therefore $ $ \frac{1}{2}=\sqrt{\frac{16}{{{M}_{X}}}} $
$ \therefore $ $ {{M}_{X}}=16\times 4=64 $
So, the molar mass of gas X is 64.
$ C{{H}_{4}} $ is $ \frac{{{r}_{x}}}{{{r}_{C{{H}_{4}}}}}=\sqrt{\frac{{{M}_{C{{H}_{4}}}}}{{{M}_{x}}}} $
Let the rate of diffusion of gas
$ X=a $ $ \therefore $
$ \frac{a}{2a}=\sqrt{\frac{16}{{{M}_{X}}}} $
( $ \because $ $ C{{H}_{4}}=12.4=16 $ )
$ \therefore $ $ \frac{1}{2}=\sqrt{\frac{16}{{{M}_{X}}}} $
$ \therefore $ $ {{M}_{X}}=16\times 4=64 $
So, the molar mass of gas X is 64.
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.