Question:

The range of a projectile of weight \( W \) is \( R \). The average torque on the projectile between the initial and final positions \( P \) and \( Q \) about the point of projection is:

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The average torque is half the product of the weight and range of the projectile.
Updated On: May 15, 2025
  • \( \frac{WR}{2} \)
  • \( \frac{WR}{3} \)
  • \( \frac{WR}{4} \)
  • \( WR \)
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The Correct Option is A

Solution and Explanation

The torque on the projectile is defined as the moment of the force at a given point. The average torque between two points \( P \) and \( Q \) on the projectile's path is given by: \[ \text{Average Torque} = \frac{1}{2} \times \text{Force} \times \text{Distance} \] Here, the force on the projectile is its weight \( W \) and the distance between \( P \) and \( Q \) is the range \( R \). Therefore, the average torque is: \[ \text{Average Torque} = \frac{WR}{2} \] Thus, the average torque between the initial and final positions \( P \) and \( Q \) is \( \frac{WR}{2} \).
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