Question:
The radius of the circle \( x^2 + y^2 - 2x - 4y - 4 = 0 \) is:
The radius of the circle \( x^2 + y^2 - 2x - 4y - 4 = 0 \) is:
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To find the radius of a circle, rearrange the equation to the standard form \( (x - h)^2 + (y - k)^2 = r^2 \), where \( r \) is the radius.
Updated On: Mar 7, 2025
- \( 2 \)
- \( 3 \)
- \( 4 \)
- \( 5 \)
- \( 6 \)
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The Correct Option is B
Solution and Explanation
Rearrange the equation of the circle to complete the square:
\[
x^2 - 2x + y^2 - 4y = 4
\]
Completing the square:
\[
(x - 1)^2 + (y - 2)^2 = 9
\]
Thus, the radius is \( 3 \).
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