The radius of the circle with centre at \((-4, 0)\) and passing through the point \((2, 8)\) is:
The radius \( r \) of a circle is the distance from the center of the circle to any point on the circle.
Given the center of the circle \((-4, 0)\) and a point on the circle \((2, 8)\), we use the distance formula to find \( r \): \[ r = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Substituting the coordinates of the center and the point: \[ r = \sqrt{(2 - (-4))^2 + (8 - 0)^2} \] \[ = \sqrt{(2 + 4)^2 + 8^2} \] \[ = \sqrt{6^2 + 8^2} \] \[ = \sqrt{36 + 64} \] \[ = \sqrt{100} \] \[ = 10 \] Thus, the radius of the circle is \( 10 \).
The area bounded by the parabola \(y = x^2 + 2\) and the lines \(y = x\), \(x = 1\) and \(x = 2\) (in square units) is:
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: