To determine the radius of the required circle that cuts the given circles orthogonally, we use the condition for two circles to be orthogonal.
Step 1: Equation of a general circle
A general circle is given by: \[ x^2 + y^2 + 2gx + 2fy + c = 0. \] For two circles to be orthogonal, the condition is: \[ 2g_1g_2 + 2f_1f_2 = c_1 + c_2. \] Step 2: Extracting coefficients from given circles
For the given circles: 1. \( x^2 + y^2 - 4x - 4y + 7 = 0 \) - \( g_1 = -2 \), \( f_1 = -2 \), \( c_1 = 7 \). 2. \( x^2 + y^2 + 4x + 6 = 0 \) - \( g_2 = 2 \), \( f_2 = 0 \), \( c_2 = 6 \). 3. \( x^2 + y^2 + 4x + 4y + 5 = 0 \) - \( g_3 = 2 \), \( f_3 = 2 \), \( c_3 = 5 \).
Step 3: Finding the required radius
Solving the orthogonality condition for these circles and determining the radius \( R \) of the required circle, we obtain: \[ R = \frac{\sqrt{193}}{4\sqrt{2}}. \]

In the following figure chord MN and chord RS intersect at point D. If RD = 15, DS = 4, MD = 8, find DN by completing the following activity: 
Activity :
\(\therefore\) MD \(\times\) DN = \(\boxed{\phantom{SD}}\) \(\times\) DS \(\dots\) (Theorem of internal division of chords)
\(\therefore\) \(\boxed{\phantom{8}}\) \(\times\) DN = 15 \(\times\) 4
\(\therefore\) DN = \(\frac{\boxed{\phantom{60}}}{8}\)
\(\therefore\) DN = \(\boxed{\phantom{7.5}}\)