Given: Initial moisture content (dry basis): $X_1 = 0.13$ Final moisture content (dry basis): $X_2 = 0.35$ Initial total mass of paddy: 50 kg
Step 1: Calculate dry matter \[ {Total mass} = {dry matter} \times (1 + X_1) \Rightarrow 50 = M_{{dry}} \cdot (1 + 0.13) \Rightarrow M_{{dry}} = \frac{50}{1.13} \approx 44.25\ {kg} \] Step 2: Calculate final total mass \[ M_{{final}} = M_{{dry}} \cdot (1 + X_2) = 44.25 \cdot 1.35 = 59.74\ {kg} \] Step 3: Calculate water added \[ {Water added} = M_{{final}} - M_{{initial}} = 59.74 - 50 = \boxed{9.74\ {kg}} \]
If the radiant temperature of a body is 360 K and its emissivity is 0.6, then the kinetic temperature of that body is __________
An engine’s torque-speed characteristics is given below:
\[ T_{maxP} = 125 \, \text{N.m}, \, N_{maxP} = 2400 \, \text{rpm}, \, N_{HI} = 2600 \, \text{rpm}, \, T_{max} = 160 \, \text{N.m}, \, N_{maxT} = 1450 \, \text{rpm} \] Where:
The Governor’s regulation is _________% (Rounded off to 2 decimal places).