The products formed in the following reaction, A and B are
The Correct Option is C
Solution and Explanation
So, the correct option is (C).
Top Questions on Hydrocarbons
- Consider the following statements
Statement I: Benzene undergoes electrophilic substitution with excess chlorine in the presence of anhydrous AlCl$_3$
Statement - II: Benzene also undergoes electrophilic substitution with chlorine in the presence of UV light.
The correct answer is- TS EAMCET - 2025
- Chemistry
- Hydrocarbons
- An alcohol 'X' (C$_4$H$_{10}$O) reacts with conc. HCl at room temperature and gives chloride. 'X' on dehydration followed by ozonolysis gives 'Y' and 'Z'. Find 'Y' and 'Z'.
- TS EAMCET - 2025
- Chemistry
- Hydrocarbons
- The empirical formula of the compound 'D' formed in the given reaction sequence is
C₂H₄ \(\xrightarrow{Br_2|CCl_4}\) A \(\xrightarrow{(i) alc. KOH (ii) NaNH_2}\) B \(\xrightarrow{cyclic\;polymerization}\) C \(\xrightarrow{Cl_2(excess), dry\;AlCl_3, dark, cold}\) D- TS EAMCET - 2025
- Chemistry
- Hydrocarbons
- An alkyne has the molecular formula C₆H₁₀. The number of 1-alkyne isomers (excluding stereoisomers) possible for it is
- TS EAMCET - 2025
- Chemistry
- Hydrocarbons
- Complete the following reactions by writing the structural formulae of ‘A’ and ‘B’:
(i) CH$_3$CH=CH$_2$ + HBr $\xrightarrow{\text{Peroxide}}$ ‘A’ $\xrightarrow{KOH}$ ‘B’
(ii) CH$_3$CH$_2$CHCl + alc. KOH $\xrightarrow{\Delta}$ ‘A’ $\xrightarrow{\text{H}_2\text{O}}$ ‘B’ (Main product)- CBSE CLASS XII - 2025
- Chemistry
- Hydrocarbons
Questions Asked in JEE Main exam
- Let the length of a latus rectum of an ellipse $ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 $ be 10. If its eccentricity is $ e $, and the minimum value of the function $ f(t) = t^2 + t + \frac{11}{12} $, where $ t \in \mathbb{R} $, then $ a^2 + b^2 $ is equal to:
- JEE Main - 2025
- Ellipse
- If the locus of $ z \in \mathbb{C} $, such that $ \text{Re} \left( \frac{z - 1}{2z + i} \right) + \text{Re} \left( \frac{ \bar{z} - 1}{2 \bar{z} - i} \right) = 2, $ is a circle of radius $ r $ and center $ (a, b) $, then $ \frac{15ab}{r^2} \text{ is equal to:} $
- JEE Main - 2025
- Complex numbers
Match the LIST-I with LIST-II
\[ \begin{array}{|l|l|} \hline \text{LIST-I} & \text{LIST-II} \\ \hline A. \ ^{236}_{92} U \rightarrow ^{94}_{38} Sr + ^{140}_{54} Xe + 2n & \text{I. Chemical Reaction} \\ \hline B. \ 2H_2 + O_2 \rightarrow 2H_2O & \text{II. Fusion with +ve Q value} \\ \hline C. \ ^3_1 H + ^2_1 H \rightarrow ^4_2 He + n & \text{III. Fission} \\ \hline D. \ ^1_1 H + ^3_1 H \rightarrow ^4_2 H + \gamma & \text{IV. Fusion with -ve Q value} \\ \hline \end{array} \]
Choose the correct answer from the options given below:
- JEE Main - 2025
- Nuclear physics
- Let $ a_n $ be the $ n $-th term of an A.P. If $ S_n = a_1 + a_2 + a_3 + \cdots + a_n = 700 $, $ a_6 = 7 $, and $ S_7 = 7 $, then $ a_n $ is equal to:
- JEE Main - 2025
- Arithmetic Progression
The number of solutions of the equation $ \cos 2\theta \cos \left( \frac{\theta}{2} \right) + \cos \left( \frac{5\theta}{2} \right) = 2 \cos^3 \left( \frac{5\theta}{2} \right) $ in the interval \(\left[ -\frac{\pi}{2}, \frac{\pi}{2} \right ]\) is:
- JEE Main - 2025
- Trigonometric Equations
Concepts Used:
Hydrocarbons - Reaction Mechanism
Hydrocarbons are organic compounds that are entirely made up of only two kinds of atoms – carbon and hydrogen. Typically, hydrocarbons are colourless gases that have very weak odours.
Mechanism of electrophilic substitution reactions:
According to experimental evidences, SE (S = substitution; E = electrophilic) reactions are supposed to proceed via the following three steps:
- Generation of the electrophile
- Formation of carbocation intermediate
- Removal of proton from the carbocation interm