The product of the oxidation of I$^-$ with MnO$_4^-$ in alkaline medium is:
Show Hint
In oxidation reactions with MnO$_4^-$, the halide is typically oxidized to a higher oxidation state, often leading to periodate (IO$_4^-$) in alkaline conditions.
When iodide ions (I$^-$) are oxidized with permanganate ions (MnO$_4^-$) in an alkaline medium, iodine gets oxidized to iodate (IO$_3^-$) and then further oxidized to periodate (IO$_4^-$). This is a typical oxidation reaction of halides by MnO$_4^-$ in basic conditions. Thus, the product is IO$_4^-$, which is option (A).