Question

The product of the following reaction is:

• A. \( \text{CH}_3 - \text{CH} = \text{CH}_2 - \text{CH}_2 - \text{OH} \)
• B. \( \text{CH}_3 - \text{CH} - \text{CH}_2 - \text{CH}_2 - \text{OH} \)
• C. \( \text{CH}_3 - \text{CH}_2 - \text{CH}_2 - \text{COOH} \)
• D. \( \text{CH}_3 - \text{CH} = \text{CH}_2 - \text{COOH} \)

Hint:

LiAlH4 is used to reduce aldehydes and ketones to alcohols, and the reaction is followed by hydrolysis.

Answer 1

The Correct Option is A

Step 1: Analyze the reaction.
The given reaction involves the reduction of an aldehyde (\( \text{CH}_3 - \text{CH} = \text{CH}_2 - \text{CHO} \)) with \( \text{LiAlH}_4 \), followed by hydrolysis with water. Lithium aluminum hydride (\( \text{LiAlH}_4 \)) is a strong reducing agent that reduces aldehydes to primary alcohols. Step 2: Determine the product.
Upon reduction of the aldehyde group and subsequent hydrolysis, the product is a primary alcohol: \[ \text{CH}_3 - \text{CH} = \text{CH}_2 - \text{CH}_2 - \text{OH} \] Thus, the correct answer is (A).