To determine the product formed in the given chemical reaction, we need to analyze the reaction conditions and the given compound.
The reaction involves the reduction of a keto group using sodium borohydride (\( \text{NaBH}_4 \)) in ethanol (\( \text{C}_2\text{H}_5\text{OH} \)). Sodium borohydride is a selective reducing agent that primarily reduces aldehydes and ketones to alcohols.
The structure of the reactant is given as:
In this compound, the carbonyl group (C=O) is present as a ketone. Sodium borohydride will reduce this ketone group to a secondary alcohol by adding hydrogen across the C=O bond.
Let's analyze what the product will look like:
The carbonyl group (C=O) gets reduced to a hydroxyl group (C-OH).
The rest of the compound remains unchanged as NaBH4 is a selective reducing agent and does not alter other functional groups in this context.
Hence, the ketone is reduced to a secondary alcohol.
Therefore, the product of the reaction is:
This is the correct answer because it shows the formation of a secondary alcohol from the reduction of the ketone group.
Organic Chemistry – Some Basic Principles and Techniques - Reaction Mechanism
SN1 Reaction Mechanism:
SN1 reaction mechanism takes place by following three steps –
Formation of carbocation
Attack of nucleophile
Deprotonation
SN2 Reaction Mechanism:
The SN2 reaction mechanism involves the nucleophilic substitution reaction of the leaving group (which generally consists of halide groups or other electron-withdrawing groups) with a nucleophile in a given organic compound.
