Let's break down the reaction step by step:
1. The starting compound is a methylstyrene derivative. The reaction with oxygen (O₂) indicates oxidation of the alkene to form a hydroxy ketone (product A).
2. The product A gives a white precipitate when treated with bromine water, which suggests the presence of a reactive alkene or phenol group. The alkene reacts with bromine, forming a dibromide.
3. The product B is treated with barium hydroxide to give product C, which indicates the formation of an alkene through dehydration.
4. Finally, compound C is heated, which suggests elimination of water, leading to the formation of alkenes.
The final product D is likely a methylpent-3-en-2-one, corresponding to Option A.
(i) What is a rate determining step?